tag:blogger.com,1999:blog-3813701770708442620.post8428174520725170376..comments2024-06-03T08:20:41.367-07:00Comments on G-FEED: The SHCIT Listsolhttp://www.blogger.com/profile/00936469103707728475noreply@blogger.comBlogger1125tag:blogger.com,1999:blog-3813701770708442620.post-75630659924916768632018-11-12T08:49:11.607-08:002018-11-12T08:49:11.607-08:00I'm reading your paper and I think I found a c...I'm reading your paper and I think I found a couple things of potential interest to you.<br /><br />On page 6 you say: "For reference, the energy from the sun reaching the top of Earth’s atmosphere is 342 W/m2".<br /><br />This is a minor nit but that is expressed the power per unit area, not the "energy".<br /><br />The second issue is more important. The solar constant is 1367 W/m2. This, of course, has to be adjusted for being distributed over half of a sphere rather than a perpendicular plane. The area of a circle, divided by one half the area of a sphere is (pi R2)/((4 pi R2)/2) which is 1/2. Hence this, unless I am missing something, results in there being about 684 W/m2 of solar energy reaching the surface of the atmosphere instead of the 342 you state in your paper.Joehttps://www.blogger.com/profile/01432474207127983686noreply@blogger.com